In 4abc c2 125 b2 325 cot c 3 2 find tan a
WebTo prove this equation non-negative, you will have to convert the equation in terms of perfect square form containing a,b and c. Now, a²+b²+c²-ab-bc-ca = ½ • ( 2a²+2b²+2c²-2ab-2bc -2ca ) = ½ • ( ... You can use Wolfram Alpha to get some alternative forms The first two listed are (A−B − C)2 −4BC A2 −2A(B +C)+ (B − C)2 As J ... Weba2 c2 + b2 c2 = c2 c2 This can be simplified to: ( a c )2 + ( b c )2 = 1 Now, a/c is Opposite / Hypotenuse, which is sin (θ) And b/c is Adjacent / Hypotenuse, which is cos (θ) So (a/c) 2 + (b/c) 2 = 1 can also be written: sin 2 θ + cos 2 θ = 1 Note: sin2 θ means to find the sine of θ, then square the result, and
In 4abc c2 125 b2 325 cot c 3 2 find tan a
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WebOct 16, 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get … WebIf a = 7, b = 3, c = 5 and a b ( tan B 2 + tan C 2 ) ( tan A 2 + tan C 2 ) + b c ( tan A 2 + tan C 2 ) ( tan A 2 + tan B 2 ) + a c ( tan B 2 + tan C 2 ) ( tan A 2 + tan B 2 ) equals k , then the value of √ k + 1 2 is
Web3cot B 2 = cot A 2cot B 2cot C 2 ⇒ cot A 2cot C 2 = 3 Now, A.M.≥G.M. ⇒ cot A 2 +cot C 2 ≥ 2√cot A 2cot C 2 ⇒ 2cot B 2 ≥2√3 ∴ cot B 2 ≥√3 Suggest Corrections 1 Similar questions Q. If ABC is a triangle and tan A 2,tan B 2,tan C 2 are in H.P., then find the minimum value of cotB/2. Q. Let A,B and C represents the angles of ABC.
WebWhat is the sum of cubes formula? The sum of cubes formula is a³ + b³ = (a+b) (a² - ab + b²) What is the difference of squares formula? The difference of squares formula is a² - b² = (a+b) (a-b) What is the difference of cubes formula? The difference of cubes formula is a³ - b³ = (a-b) (a² + ab + b²) WebUsing the Law of Cosines we also have: a 2 = b 2 +c 2 -2bccosA b 2 = a 2 +c 2 -2accosB c 2 = a 2 +b 2 -2abcosC The trick is to add these three equations together, simplify, divide by 4, and then replace 1/2 ac with K/sinB (for example). a 2 +b 2 +c 2 =2a 2 +2b 2 +2c 2 -2bccosA-2accosB-2abcosC This can be rewritten as:
WebSolve an equation, inequality or a system. Example: 2x-1=y,2y+3=x. 1: 2: 3: 4: 5: 6: 7: 8: 9: 0., < > ≤: ≥ ^ √: ⬅: : F _ ÷ (* / ⌫ A: ↻: x: y = +-G
WebIf tan A 2,tan B 2,tan C 2 are in H.P., then the minimum value of cot B 2 is. Q. If ABC is triangle and tan A 2,tan B 2,tan C 2 are in H.P the find the minimum value of cot B 2. Q. If … microsoft outlook reply email shrunkWeba2 (b-c)+b2 (c-a)+c2 (a-b)>0 Reformatting the input : Changes made to your input should not affect the solution: (1): "c2" was replaced by "c^2". 2 more similar replacement (s). Step by … how to create a sorted list in javaWebSymbolab is the best step by step calculator for a wide range of math problems, from basic arithmetic to advanced calculus and linear algebra. It shows you the solution, graph, detailed steps and explanations for each problem. how to create a sopWebClick here👆to get an answer to your question ️ In a ABC if b + c = 3a , then cot B2 .cot C2 has the value equal to. Solve Study Textbooks Guides. Join / Login. ... Verified by Toppr. … how to create a sop manualWebJan 20, 2024 · 2 Answers Sorted by: 1 If x = tanC, and we have cos2A = cos2B, we need to minimize (x − sinA)2 + (1 x − cosA)2 = x2 + 1 x2 + 1 − 2(xsinA + cosA x) So, we need to maximize (xsinA + cosA x). It is known that maximum of αsinθ + βcosθ is √α2 + β2 , so it's maximum is √x2 + 1 x2, so our expression becomes x2 + 1 x2 − 2√x2 + 1 x2 + 1 = (√x2 + 1 … microsoft outlook reply greyed outWebApr 13, 2024 · Sorted by: 1. The following identity is very useful. tan A 2 tan B 2 + tan A 2 tan C 2 + tan B 2 tan C 2 = 1. From here C = 90 ∘. We can get this result by geometric way. Let … how to create a sop templateWebCorrect option is A) Given that A,B and C are vertices of a ABC The coordinate of B and C are (2,0) and (8,0) ∴ a=8−α=6 units we can assume the coordinate of A to be (x,y) ⇒b= (x−2) 2+y 2,c= (x−8) 2+y 2 From half angle formulas tan 2B= s(s−b)(s−a)(s−c) and tan 2c= s(s−c)(s−a)(s−b) s= 2a+b+c i.e, perimeter. Given that 4tan 2Btan 2C=1 microsoft outlook report phishing