WebMathematics In a triangle, if r1 = 2 r2 = 3r3, then (a/b) + (b/c) + (c/a) is equal to Q. In a triangle, if r1 = 2r2 = 3r3, then ba + cb + ac is equal to 2475 46 BITSAT BITSAT 2008 Report Error A 6075 B 60155 C 60176 D 60191 Solution: Given that, r1 = 2r2 = 3r3 ∴ s−aΔ = s−b2Δ = s−c3Δ = kΔ Then, s−a = k,s− b = 2k,s−c = 3k ⇒ 3x −(a+ b+ c) = 6k WebIf (r2–r1) (r3–r1) = 2r2r3. Show that A = 90. please give the answer avinash, 5 years ago Grade:11 2 Answers Harsh Patodia IIT Roorkee askIITians Faculty 907 Points 5 years ago Abin Beni 13 Points 4 years ago Do the same and at the last step 0 = (b^2+c^2-a^2) TO proove angle A=90 Divide by 2bc, 0 = (b^2+c^2+a^2)/2bc
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WebStep 2: Determine the ratio. Since two angles are equal, the triangle is an isosceles right angle triangle and hence two sides will be equal. Therefore let sides a = k, b = k. Thus we have, by the converse of Pythagoras theorem. c = a 2 + b 2 = k 2 + k 2 = 2 k 2 c = 2 k. The ratio of a: b: c is 1 k: 1 k: 2 k o r 1: 1: 2. WebCorrect option is B) Given that r 1r 2r 3 are radii of ex-circles, we have the following relations r 1= s−aΔ,r 2= s−bΔ,r 3= s−cΔ where Δ is the area of the triangle ABC having lengths of the sides a,b,c and 2s= a+b+c Also given r 1=2r 2=3r 3 So r 2r 1=2 ⇒ s−as−b=2 ⇒s−b−2s=−2a ⇒s+b−2a=0 ⇒2s+2b−4a=0 ⇒a+b+c+2b−4a=0 ⇒c+3b−3a=0 ⇒c+3b−3a=0 ⇒c=3a−3b birthday rsvp app
If in a Δ ABC, r1 = 2r2 = 3r3 , then the perimeter of the triangle is ...
WebJul 21, 2024 · answered If in a triangle abc , r1 = 2r2 = 3r3 , then b:c = ? Advertisement Answer 1 person found it helpful kusumlata971988 Step-by-step explanation: … WebJun 27, 2016 · Explanation: Multiplying both sides by 2 in given equality cosAcosB + sinAsinBsinC = 1, we get 2cosAcosB +2sinAsinBsinC = 2 or 2cosAcosB +2sinAsinBsinC = (sin2A +cos2A) + (sin2B + cos2B) or (cos2A+ cos2B − 2cosAcosB) +(sin2A+ sin2B −2sinAsinB) + 2sinAsinB − 2sinAsinBsinC = 0 or or (cosA− cosB)2 + (sinA −sinB)2 + … WebOct 17, 2024 · If r1 = r+ r2 + r3, then prove that the triangle is a right angled triangle. triangle jee jee mains 1 Answer +1 vote answered Oct 17, 2024 by Abhinav03 (64.8k points) selected Oct 18, 2024 by Radhika01 Best answer r1 – r = r2 + r3 ∆/ (s - a) - ∆/s = ∆/ (s - b) + ∆/ (s - c) ⇒ ∆a/s (s - a) = ∆a/ ( (s - b) (s - c)) ⇒ s (s - a) = (s - b) (s - c) dantdm jelly bean challenge